Can the Right Ascension and Argument of Perigee of a spacecraft's orbit keep varying by themselves with time? The 2019 Stack Overflow Developer Survey Results Are InHow is the altitude of a satellite defined, given that the Earth is not spherical?Why do satellites appear to move faster when overhead and slower closer to the horizon?For the mathematical relationship between J2 (km^5/s^2) and dimensionless J2 - which one is derived from the other?Why is Nodal precession affected by the rotational period of the planet?Why is it so difficult to predict the exact reentry location and time of a very low earth orbit object?Why are low earth orbit satellites not visible from the same place all the time?Perifocal coordinates and the orbit equationHow feasible is the Moonspike mission?What was the typical perigee after a shuttle de-orbit burn?I am having trouble calculating my classic orbital elements and am at a loss on where to lookAm I supposed to modify the gravitational constant with scale and why do fps & time scale changes cause my orbit to break?How Local time of a sun synchronous orbit is related to Right ascension of ascending node?What is wrong with my orbit sim equations? How can I fix them?How to obtain the initial positions and velocities of an inclined orbit?

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Can the Right Ascension and Argument of Perigee of a spacecraft's orbit keep varying by themselves with time?



The 2019 Stack Overflow Developer Survey Results Are InHow is the altitude of a satellite defined, given that the Earth is not spherical?Why do satellites appear to move faster when overhead and slower closer to the horizon?For the mathematical relationship between J2 (km^5/s^2) and dimensionless J2 - which one is derived from the other?Why is Nodal precession affected by the rotational period of the planet?Why is it so difficult to predict the exact reentry location and time of a very low earth orbit object?Why are low earth orbit satellites not visible from the same place all the time?Perifocal coordinates and the orbit equationHow feasible is the Moonspike mission?What was the typical perigee after a shuttle de-orbit burn?I am having trouble calculating my classic orbital elements and am at a loss on where to lookAm I supposed to modify the gravitational constant with scale and why do fps & time scale changes cause my orbit to break?How Local time of a sun synchronous orbit is related to Right ascension of ascending node?What is wrong with my orbit sim equations? How can I fix them?How to obtain the initial positions and velocities of an inclined orbit?










6












$begingroup$


I came across the orbital data for a low Earth orbit spacecraft and one thing which I am not able to understand is why does its Right Ascension of ascending node and Argument of Perigee keep changing every day.



Firstly, it seems extremely unrealistic to me, that they are being changed by manoeuvring the spacecraft because:



  1. They are very costly affairs and for doing them over the period of months, one would need a mammoth amount of propellant.

  2. I can't see what purpose it would serve.

So, to me it looks like they are either changing by themselves or the orbital data itself is wrong. I suspect the data being wrong as I haven't come across any phenomenon where orbital plane keeps changing and and also rotating by itself with time. It would require strong external disturbances for that to happen by itself and I doubt there are such strong and sustaining disturbances acting on the spacecraft. So, is the data incorrect?



Edit: I checked data for two more spacecrafts on the same website and they also seem to be behaving similarly. This is either something I don't know of, or the data is garbage.










share|improve this question











$endgroup$
















    6












    $begingroup$


    I came across the orbital data for a low Earth orbit spacecraft and one thing which I am not able to understand is why does its Right Ascension of ascending node and Argument of Perigee keep changing every day.



    Firstly, it seems extremely unrealistic to me, that they are being changed by manoeuvring the spacecraft because:



    1. They are very costly affairs and for doing them over the period of months, one would need a mammoth amount of propellant.

    2. I can't see what purpose it would serve.

    So, to me it looks like they are either changing by themselves or the orbital data itself is wrong. I suspect the data being wrong as I haven't come across any phenomenon where orbital plane keeps changing and and also rotating by itself with time. It would require strong external disturbances for that to happen by itself and I doubt there are such strong and sustaining disturbances acting on the spacecraft. So, is the data incorrect?



    Edit: I checked data for two more spacecrafts on the same website and they also seem to be behaving similarly. This is either something I don't know of, or the data is garbage.










    share|improve this question











    $endgroup$














      6












      6








      6





      $begingroup$


      I came across the orbital data for a low Earth orbit spacecraft and one thing which I am not able to understand is why does its Right Ascension of ascending node and Argument of Perigee keep changing every day.



      Firstly, it seems extremely unrealistic to me, that they are being changed by manoeuvring the spacecraft because:



      1. They are very costly affairs and for doing them over the period of months, one would need a mammoth amount of propellant.

      2. I can't see what purpose it would serve.

      So, to me it looks like they are either changing by themselves or the orbital data itself is wrong. I suspect the data being wrong as I haven't come across any phenomenon where orbital plane keeps changing and and also rotating by itself with time. It would require strong external disturbances for that to happen by itself and I doubt there are such strong and sustaining disturbances acting on the spacecraft. So, is the data incorrect?



      Edit: I checked data for two more spacecrafts on the same website and they also seem to be behaving similarly. This is either something I don't know of, or the data is garbage.










      share|improve this question











      $endgroup$




      I came across the orbital data for a low Earth orbit spacecraft and one thing which I am not able to understand is why does its Right Ascension of ascending node and Argument of Perigee keep changing every day.



      Firstly, it seems extremely unrealistic to me, that they are being changed by manoeuvring the spacecraft because:



      1. They are very costly affairs and for doing them over the period of months, one would need a mammoth amount of propellant.

      2. I can't see what purpose it would serve.

      So, to me it looks like they are either changing by themselves or the orbital data itself is wrong. I suspect the data being wrong as I haven't come across any phenomenon where orbital plane keeps changing and and also rotating by itself with time. It would require strong external disturbances for that to happen by itself and I doubt there are such strong and sustaining disturbances acting on the spacecraft. So, is the data incorrect?



      Edit: I checked data for two more spacecrafts on the same website and they also seem to be behaving similarly. This is either something I don't know of, or the data is garbage.







      spacecraft low-earth-orbit orbital-elements






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 4 hours ago







      Niket

















      asked 4 hours ago









      NiketNiket

      404




      404




















          2 Answers
          2






          active

          oldest

          votes


















          6












          $begingroup$

          You are correct to a point that the RA of the ascending node and argument of perigee won't change over time without some external force acting upon the satellite. In a simplified gravitational field, an object's orbital plane remains fixed.



          Unfortunately, reality is a lot more messy.



          Earth's gravitational field differs significantly from that created by a hypothetical point mass - this is known as the Geopotential Model. In particular, the Earth's oblateness (equatorial bulge), defined by the J2 coefficient, has a significant effect on orbits. It causes them to precess over time, changing the RA/longitude of their ascending nodes.



          Furthermore, perturbing influences from other bodies in the solar system need to be accounted for when accurately plotting orbits - they can have small but non-negligible effects.



          As to your second point, these effects can be very useful for satellites. For example, Sun Synchronous Orbits are precisely designed to precess at a rate of 360° per year, maintaining a constant angle between the orbital plane and the sun. This is ideal eg. for keeping a fixed illumination for surface observation.



          See this related question on J2 pertubations for some more detail on the maths.






          share|improve this answer











          $endgroup$












          • $begingroup$
            I see. Just to be sure, is the data realistic? Like does the day to day variation seem realistic?
            $endgroup$
            – Niket
            3 hours ago






          • 4




            $begingroup$
            The data looks realistic. The change in RAAN is only around half a degree per day, which is a realistic precession for this inclination. The fact that the argument of perigee changes so drastically I think is due to the low eccentricity. Basically if your orbit is as good as circular, small perturbations can change the argument of perigee drastically.
            $endgroup$
            – Alexander Vandenberghe
            1 hour ago










          • $begingroup$
            @Niket I agree with Alexander Vandenberghe's comment. The very low eccentricity is causing the rapid changes in the argument of periapsis
            $endgroup$
            – Jack
            1 hour ago



















          2












          $begingroup$

          @Jack's answer is excellent, I'll just address @Niket's question in this comment a little further.




          Just to be sure, is the data realistic? Like does the day to day variation seem realistic?




          tl;dr: The drift makes sense and is within 1% of what we can easily calculate.




          There are some of the orbital parameters plotted at the bottom of the page. The RA of the ascending node cycles through 360 degrees in about 60 days. That's about right for a ~45 degree inclined orbit in LEO, the ISS does that.



          It's a big deal for the ISS because it means it cycles through periods where it goes into Earth's shadow every 90 minutes and then periods where it's in constant daylight as its orbital plane rotates around the Earth.



          Let's see if we can calculate it. From this answer:




          The first equation in Wikipedia's Nodal precession for the rate of precession $omega_p$:



          $$omega_p = -frac32 fracR_E^2(a(1-epsilon^2))^2 J_2 omega cos(i)$$



          depends on the parameters of the orbit ($a, epsilon, omega$, i) and the Earth's equatorial radius $R_E$ and its $J_2$ term.




          Let's use 6378137 meters for $R_E$ (from this answer) and 1.0826E-03 for $J_2$ (from this answer).



          The satellite's period $T$ in your data table is 15.59029 revolutions per day, or about 5542 seconds. Then use:



          $$omega = frac2 piT = 0.0011338 textsec^-1.$$



          From this answer get



          $$a^3 = fracGMomega^2$$



          where GM is Earth's standard gravitational parameter of about 3.986E+14 m^3/s^2. That makes $a=$ 6768601 meters, or an altitude of about 390 km.



          Plug those all in to the first equation, and we get $omega_p = -1.2149 times 10^-6 textsec^-1$ If we multiply that by 60 days or 5184000 seconds, we get -6.298 which is almost exactly $-2 pi$ or one complete cycle, just what the plot shows!



          The argument of perihelion at first looks like it drifts steadily then flips by 180 degrees around day 85, but that's actually a smooth shape change since the eccentricity hits zero and bounces back. That looks like a natural precession as well, and not an orbital maneuver.



          So @Jack's answer nailed it.



          Python script for the plot is available here: https://pastebin.com/rx1np9Mv



          enter image description here






          share|improve this answer











          $endgroup$













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            2 Answers
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            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            6












            $begingroup$

            You are correct to a point that the RA of the ascending node and argument of perigee won't change over time without some external force acting upon the satellite. In a simplified gravitational field, an object's orbital plane remains fixed.



            Unfortunately, reality is a lot more messy.



            Earth's gravitational field differs significantly from that created by a hypothetical point mass - this is known as the Geopotential Model. In particular, the Earth's oblateness (equatorial bulge), defined by the J2 coefficient, has a significant effect on orbits. It causes them to precess over time, changing the RA/longitude of their ascending nodes.



            Furthermore, perturbing influences from other bodies in the solar system need to be accounted for when accurately plotting orbits - they can have small but non-negligible effects.



            As to your second point, these effects can be very useful for satellites. For example, Sun Synchronous Orbits are precisely designed to precess at a rate of 360° per year, maintaining a constant angle between the orbital plane and the sun. This is ideal eg. for keeping a fixed illumination for surface observation.



            See this related question on J2 pertubations for some more detail on the maths.






            share|improve this answer











            $endgroup$












            • $begingroup$
              I see. Just to be sure, is the data realistic? Like does the day to day variation seem realistic?
              $endgroup$
              – Niket
              3 hours ago






            • 4




              $begingroup$
              The data looks realistic. The change in RAAN is only around half a degree per day, which is a realistic precession for this inclination. The fact that the argument of perigee changes so drastically I think is due to the low eccentricity. Basically if your orbit is as good as circular, small perturbations can change the argument of perigee drastically.
              $endgroup$
              – Alexander Vandenberghe
              1 hour ago










            • $begingroup$
              @Niket I agree with Alexander Vandenberghe's comment. The very low eccentricity is causing the rapid changes in the argument of periapsis
              $endgroup$
              – Jack
              1 hour ago
















            6












            $begingroup$

            You are correct to a point that the RA of the ascending node and argument of perigee won't change over time without some external force acting upon the satellite. In a simplified gravitational field, an object's orbital plane remains fixed.



            Unfortunately, reality is a lot more messy.



            Earth's gravitational field differs significantly from that created by a hypothetical point mass - this is known as the Geopotential Model. In particular, the Earth's oblateness (equatorial bulge), defined by the J2 coefficient, has a significant effect on orbits. It causes them to precess over time, changing the RA/longitude of their ascending nodes.



            Furthermore, perturbing influences from other bodies in the solar system need to be accounted for when accurately plotting orbits - they can have small but non-negligible effects.



            As to your second point, these effects can be very useful for satellites. For example, Sun Synchronous Orbits are precisely designed to precess at a rate of 360° per year, maintaining a constant angle between the orbital plane and the sun. This is ideal eg. for keeping a fixed illumination for surface observation.



            See this related question on J2 pertubations for some more detail on the maths.






            share|improve this answer











            $endgroup$












            • $begingroup$
              I see. Just to be sure, is the data realistic? Like does the day to day variation seem realistic?
              $endgroup$
              – Niket
              3 hours ago






            • 4




              $begingroup$
              The data looks realistic. The change in RAAN is only around half a degree per day, which is a realistic precession for this inclination. The fact that the argument of perigee changes so drastically I think is due to the low eccentricity. Basically if your orbit is as good as circular, small perturbations can change the argument of perigee drastically.
              $endgroup$
              – Alexander Vandenberghe
              1 hour ago










            • $begingroup$
              @Niket I agree with Alexander Vandenberghe's comment. The very low eccentricity is causing the rapid changes in the argument of periapsis
              $endgroup$
              – Jack
              1 hour ago














            6












            6








            6





            $begingroup$

            You are correct to a point that the RA of the ascending node and argument of perigee won't change over time without some external force acting upon the satellite. In a simplified gravitational field, an object's orbital plane remains fixed.



            Unfortunately, reality is a lot more messy.



            Earth's gravitational field differs significantly from that created by a hypothetical point mass - this is known as the Geopotential Model. In particular, the Earth's oblateness (equatorial bulge), defined by the J2 coefficient, has a significant effect on orbits. It causes them to precess over time, changing the RA/longitude of their ascending nodes.



            Furthermore, perturbing influences from other bodies in the solar system need to be accounted for when accurately plotting orbits - they can have small but non-negligible effects.



            As to your second point, these effects can be very useful for satellites. For example, Sun Synchronous Orbits are precisely designed to precess at a rate of 360° per year, maintaining a constant angle between the orbital plane and the sun. This is ideal eg. for keeping a fixed illumination for surface observation.



            See this related question on J2 pertubations for some more detail on the maths.






            share|improve this answer











            $endgroup$



            You are correct to a point that the RA of the ascending node and argument of perigee won't change over time without some external force acting upon the satellite. In a simplified gravitational field, an object's orbital plane remains fixed.



            Unfortunately, reality is a lot more messy.



            Earth's gravitational field differs significantly from that created by a hypothetical point mass - this is known as the Geopotential Model. In particular, the Earth's oblateness (equatorial bulge), defined by the J2 coefficient, has a significant effect on orbits. It causes them to precess over time, changing the RA/longitude of their ascending nodes.



            Furthermore, perturbing influences from other bodies in the solar system need to be accounted for when accurately plotting orbits - they can have small but non-negligible effects.



            As to your second point, these effects can be very useful for satellites. For example, Sun Synchronous Orbits are precisely designed to precess at a rate of 360° per year, maintaining a constant angle between the orbital plane and the sun. This is ideal eg. for keeping a fixed illumination for surface observation.



            See this related question on J2 pertubations for some more detail on the maths.







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 52 mins ago

























            answered 4 hours ago









            JackJack

            8,15513555




            8,15513555











            • $begingroup$
              I see. Just to be sure, is the data realistic? Like does the day to day variation seem realistic?
              $endgroup$
              – Niket
              3 hours ago






            • 4




              $begingroup$
              The data looks realistic. The change in RAAN is only around half a degree per day, which is a realistic precession for this inclination. The fact that the argument of perigee changes so drastically I think is due to the low eccentricity. Basically if your orbit is as good as circular, small perturbations can change the argument of perigee drastically.
              $endgroup$
              – Alexander Vandenberghe
              1 hour ago










            • $begingroup$
              @Niket I agree with Alexander Vandenberghe's comment. The very low eccentricity is causing the rapid changes in the argument of periapsis
              $endgroup$
              – Jack
              1 hour ago

















            • $begingroup$
              I see. Just to be sure, is the data realistic? Like does the day to day variation seem realistic?
              $endgroup$
              – Niket
              3 hours ago






            • 4




              $begingroup$
              The data looks realistic. The change in RAAN is only around half a degree per day, which is a realistic precession for this inclination. The fact that the argument of perigee changes so drastically I think is due to the low eccentricity. Basically if your orbit is as good as circular, small perturbations can change the argument of perigee drastically.
              $endgroup$
              – Alexander Vandenberghe
              1 hour ago










            • $begingroup$
              @Niket I agree with Alexander Vandenberghe's comment. The very low eccentricity is causing the rapid changes in the argument of periapsis
              $endgroup$
              – Jack
              1 hour ago
















            $begingroup$
            I see. Just to be sure, is the data realistic? Like does the day to day variation seem realistic?
            $endgroup$
            – Niket
            3 hours ago




            $begingroup$
            I see. Just to be sure, is the data realistic? Like does the day to day variation seem realistic?
            $endgroup$
            – Niket
            3 hours ago




            4




            4




            $begingroup$
            The data looks realistic. The change in RAAN is only around half a degree per day, which is a realistic precession for this inclination. The fact that the argument of perigee changes so drastically I think is due to the low eccentricity. Basically if your orbit is as good as circular, small perturbations can change the argument of perigee drastically.
            $endgroup$
            – Alexander Vandenberghe
            1 hour ago




            $begingroup$
            The data looks realistic. The change in RAAN is only around half a degree per day, which is a realistic precession for this inclination. The fact that the argument of perigee changes so drastically I think is due to the low eccentricity. Basically if your orbit is as good as circular, small perturbations can change the argument of perigee drastically.
            $endgroup$
            – Alexander Vandenberghe
            1 hour ago












            $begingroup$
            @Niket I agree with Alexander Vandenberghe's comment. The very low eccentricity is causing the rapid changes in the argument of periapsis
            $endgroup$
            – Jack
            1 hour ago





            $begingroup$
            @Niket I agree with Alexander Vandenberghe's comment. The very low eccentricity is causing the rapid changes in the argument of periapsis
            $endgroup$
            – Jack
            1 hour ago












            2












            $begingroup$

            @Jack's answer is excellent, I'll just address @Niket's question in this comment a little further.




            Just to be sure, is the data realistic? Like does the day to day variation seem realistic?




            tl;dr: The drift makes sense and is within 1% of what we can easily calculate.




            There are some of the orbital parameters plotted at the bottom of the page. The RA of the ascending node cycles through 360 degrees in about 60 days. That's about right for a ~45 degree inclined orbit in LEO, the ISS does that.



            It's a big deal for the ISS because it means it cycles through periods where it goes into Earth's shadow every 90 minutes and then periods where it's in constant daylight as its orbital plane rotates around the Earth.



            Let's see if we can calculate it. From this answer:




            The first equation in Wikipedia's Nodal precession for the rate of precession $omega_p$:



            $$omega_p = -frac32 fracR_E^2(a(1-epsilon^2))^2 J_2 omega cos(i)$$



            depends on the parameters of the orbit ($a, epsilon, omega$, i) and the Earth's equatorial radius $R_E$ and its $J_2$ term.




            Let's use 6378137 meters for $R_E$ (from this answer) and 1.0826E-03 for $J_2$ (from this answer).



            The satellite's period $T$ in your data table is 15.59029 revolutions per day, or about 5542 seconds. Then use:



            $$omega = frac2 piT = 0.0011338 textsec^-1.$$



            From this answer get



            $$a^3 = fracGMomega^2$$



            where GM is Earth's standard gravitational parameter of about 3.986E+14 m^3/s^2. That makes $a=$ 6768601 meters, or an altitude of about 390 km.



            Plug those all in to the first equation, and we get $omega_p = -1.2149 times 10^-6 textsec^-1$ If we multiply that by 60 days or 5184000 seconds, we get -6.298 which is almost exactly $-2 pi$ or one complete cycle, just what the plot shows!



            The argument of perihelion at first looks like it drifts steadily then flips by 180 degrees around day 85, but that's actually a smooth shape change since the eccentricity hits zero and bounces back. That looks like a natural precession as well, and not an orbital maneuver.



            So @Jack's answer nailed it.



            Python script for the plot is available here: https://pastebin.com/rx1np9Mv



            enter image description here






            share|improve this answer











            $endgroup$

















              2












              $begingroup$

              @Jack's answer is excellent, I'll just address @Niket's question in this comment a little further.




              Just to be sure, is the data realistic? Like does the day to day variation seem realistic?




              tl;dr: The drift makes sense and is within 1% of what we can easily calculate.




              There are some of the orbital parameters plotted at the bottom of the page. The RA of the ascending node cycles through 360 degrees in about 60 days. That's about right for a ~45 degree inclined orbit in LEO, the ISS does that.



              It's a big deal for the ISS because it means it cycles through periods where it goes into Earth's shadow every 90 minutes and then periods where it's in constant daylight as its orbital plane rotates around the Earth.



              Let's see if we can calculate it. From this answer:




              The first equation in Wikipedia's Nodal precession for the rate of precession $omega_p$:



              $$omega_p = -frac32 fracR_E^2(a(1-epsilon^2))^2 J_2 omega cos(i)$$



              depends on the parameters of the orbit ($a, epsilon, omega$, i) and the Earth's equatorial radius $R_E$ and its $J_2$ term.




              Let's use 6378137 meters for $R_E$ (from this answer) and 1.0826E-03 for $J_2$ (from this answer).



              The satellite's period $T$ in your data table is 15.59029 revolutions per day, or about 5542 seconds. Then use:



              $$omega = frac2 piT = 0.0011338 textsec^-1.$$



              From this answer get



              $$a^3 = fracGMomega^2$$



              where GM is Earth's standard gravitational parameter of about 3.986E+14 m^3/s^2. That makes $a=$ 6768601 meters, or an altitude of about 390 km.



              Plug those all in to the first equation, and we get $omega_p = -1.2149 times 10^-6 textsec^-1$ If we multiply that by 60 days or 5184000 seconds, we get -6.298 which is almost exactly $-2 pi$ or one complete cycle, just what the plot shows!



              The argument of perihelion at first looks like it drifts steadily then flips by 180 degrees around day 85, but that's actually a smooth shape change since the eccentricity hits zero and bounces back. That looks like a natural precession as well, and not an orbital maneuver.



              So @Jack's answer nailed it.



              Python script for the plot is available here: https://pastebin.com/rx1np9Mv



              enter image description here






              share|improve this answer











              $endgroup$















                2












                2








                2





                $begingroup$

                @Jack's answer is excellent, I'll just address @Niket's question in this comment a little further.




                Just to be sure, is the data realistic? Like does the day to day variation seem realistic?




                tl;dr: The drift makes sense and is within 1% of what we can easily calculate.




                There are some of the orbital parameters plotted at the bottom of the page. The RA of the ascending node cycles through 360 degrees in about 60 days. That's about right for a ~45 degree inclined orbit in LEO, the ISS does that.



                It's a big deal for the ISS because it means it cycles through periods where it goes into Earth's shadow every 90 minutes and then periods where it's in constant daylight as its orbital plane rotates around the Earth.



                Let's see if we can calculate it. From this answer:




                The first equation in Wikipedia's Nodal precession for the rate of precession $omega_p$:



                $$omega_p = -frac32 fracR_E^2(a(1-epsilon^2))^2 J_2 omega cos(i)$$



                depends on the parameters of the orbit ($a, epsilon, omega$, i) and the Earth's equatorial radius $R_E$ and its $J_2$ term.




                Let's use 6378137 meters for $R_E$ (from this answer) and 1.0826E-03 for $J_2$ (from this answer).



                The satellite's period $T$ in your data table is 15.59029 revolutions per day, or about 5542 seconds. Then use:



                $$omega = frac2 piT = 0.0011338 textsec^-1.$$



                From this answer get



                $$a^3 = fracGMomega^2$$



                where GM is Earth's standard gravitational parameter of about 3.986E+14 m^3/s^2. That makes $a=$ 6768601 meters, or an altitude of about 390 km.



                Plug those all in to the first equation, and we get $omega_p = -1.2149 times 10^-6 textsec^-1$ If we multiply that by 60 days or 5184000 seconds, we get -6.298 which is almost exactly $-2 pi$ or one complete cycle, just what the plot shows!



                The argument of perihelion at first looks like it drifts steadily then flips by 180 degrees around day 85, but that's actually a smooth shape change since the eccentricity hits zero and bounces back. That looks like a natural precession as well, and not an orbital maneuver.



                So @Jack's answer nailed it.



                Python script for the plot is available here: https://pastebin.com/rx1np9Mv



                enter image description here






                share|improve this answer











                $endgroup$



                @Jack's answer is excellent, I'll just address @Niket's question in this comment a little further.




                Just to be sure, is the data realistic? Like does the day to day variation seem realistic?




                tl;dr: The drift makes sense and is within 1% of what we can easily calculate.




                There are some of the orbital parameters plotted at the bottom of the page. The RA of the ascending node cycles through 360 degrees in about 60 days. That's about right for a ~45 degree inclined orbit in LEO, the ISS does that.



                It's a big deal for the ISS because it means it cycles through periods where it goes into Earth's shadow every 90 minutes and then periods where it's in constant daylight as its orbital plane rotates around the Earth.



                Let's see if we can calculate it. From this answer:




                The first equation in Wikipedia's Nodal precession for the rate of precession $omega_p$:



                $$omega_p = -frac32 fracR_E^2(a(1-epsilon^2))^2 J_2 omega cos(i)$$



                depends on the parameters of the orbit ($a, epsilon, omega$, i) and the Earth's equatorial radius $R_E$ and its $J_2$ term.




                Let's use 6378137 meters for $R_E$ (from this answer) and 1.0826E-03 for $J_2$ (from this answer).



                The satellite's period $T$ in your data table is 15.59029 revolutions per day, or about 5542 seconds. Then use:



                $$omega = frac2 piT = 0.0011338 textsec^-1.$$



                From this answer get



                $$a^3 = fracGMomega^2$$



                where GM is Earth's standard gravitational parameter of about 3.986E+14 m^3/s^2. That makes $a=$ 6768601 meters, or an altitude of about 390 km.



                Plug those all in to the first equation, and we get $omega_p = -1.2149 times 10^-6 textsec^-1$ If we multiply that by 60 days or 5184000 seconds, we get -6.298 which is almost exactly $-2 pi$ or one complete cycle, just what the plot shows!



                The argument of perihelion at first looks like it drifts steadily then flips by 180 degrees around day 85, but that's actually a smooth shape change since the eccentricity hits zero and bounces back. That looks like a natural precession as well, and not an orbital maneuver.



                So @Jack's answer nailed it.



                Python script for the plot is available here: https://pastebin.com/rx1np9Mv



                enter image description here







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 31 mins ago

























                answered 45 mins ago









                uhohuhoh

                40.8k18152516




                40.8k18152516



























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